You can see some of these played out as an animation in various Java applets on the 'Net. For example, try this site.
You can use Maple to get a feel for just how difficult untangling the motions might be. Take a look here for a module on relative circular motion.
Sometime during the period of 1665-1666, Newton returned home to his mother's farm since the university was closed due to the plague. While there, Newton, according to his own words, considered the problem of planetary motion and focused on coming up with a theory to explain the motion of the moon around the earth. Newton's view, for which there is considerable doubt, is that he had at hand all the information to consider a thought experiment in which the same gravitational force that pulls a falling apple to the ground could be the same force that holds the moon in orbit around the earth. In fact, most of the information Newton needed was not clearly dilineated until after 1675, but the thought experiment is impressive and informative nonetheless. It begins with Newton's statement "as the power [of gravity] is not found sensibly diminished at the remotest distance from the center of the Earth to which we can rise, neither at the tops of the loftiest buildings, not even the summits of the highest mountains; it appeared reasonable to conclude that this power must extend much further than is usually thought; why not as high as the Moon; and if so, her motion must be influenced by it; perhaps she is retained in her orbit thereby."
"as the power [of gravity] is not found sensibly diminished at the remotest distance from the center of the Earth to which we can rise, neither at the tops of the loftiest buildings, not even the summits of the highest mountains; it appeared reasonable to conclude that this power must extend much further than is usually thought; why not as high as the Moon; and if so, her motion must be influenced by it; perhaps she is retained in her orbit thereby."
The thought experiment begins with Kepler's third law applied to circular orbits. It continues with Christian Huygen's publication, in 1673, of the formula for the centripetal acceleration of a body in a circular orbit, ar = 4p2r/T2. By 1679, Robert Hooke, Edmund Hillary, and Christopher Wren had shown that, for a circular orbit, the force delivering the centripetal acceleration must have a strength which is proportional to 1/r2 to fit in with Kepler's Third Law for planetary orbits. This is easy to see. Consider a point object with a mass m, a non-zero, constant velocity and a centripetal force acting on it toward a central body as shown below.
We have ar = v2/r. The period of the circular orbit must be T = 2pr/v, therefore,
This result from Huygen can be combined with Kepler's 3rd Law, T2 = kr3, to show that the force providing ar must vary as 1/r2
So the central force is proportional to 1/r2. The 1/r2 form is also reasonable from the isotropy of space argument presented in the text.
With the knowledge that, at least for circular orbits, the central force must vary as 1/r2 and knowledge that the distance from the center of the earth to the center of the moon is about 60 earth radii, Newton could perform the quick calculation that the acceleration toward the center of the earth of an apple near the surface of the earth is consistent with the moon being attracted to the center of the earth by the same force, as long as that force varies as 1/r2. Say that the magnitude of the acceleration a body experiences due to the gravitational attraction of the earth is ar = kearth/r2 where r is the distance from the center of the earth. Then kearth = arr2. For the apple, r = Rearth = 6.37 x 106 m. For the moon, r = Re-m = 60Rearth. Therefore, if the same earth is responsible for the motion of a falling apple and the curved orbit of the moon, then aappleRearth2 = amoonRe-m(60Rearth)2, so, using our established connection between centripetal acceleration and period of orbit, we find
The actual sidereal time for one complete lunar orbit is 27.3 days so Newton's guess about gravity being the same force that causes the motion of a falling apple and the orbiting moon looks to be correct or, in Newton's words, "I deduced that the forces which keep the planets in their orbs must be reciprocally as the squares of their distances from the centers about which they revolve; and thereby compared the force requisite to keep the Moon in her orb with the force of gravity at the surface of the Earth; and found them answer pretty nearly."
"I deduced that the forces which keep the planets in their orbs must be reciprocally as the squares of their distances from the centers about which they revolve; and thereby compared the force requisite to keep the Moon in her orb with the force of gravity at the surface of the Earth; and found them answer pretty nearly."
This is a remarkable advance! Newton has shown that the same laws of motion that we study on earth are applicable to the motions of bodies far beyond the environs of earth. Laboratory experiments here can be used to deduce theories of nature which are universally applicable.
The remaining things for Newton to do to come up with a complete theory of gravity were non-trivial. First, he had to be clear in his notions about his second and third laws of motion (he had already a clear concept of inertia), he had to reconcile his results with the fact that the orbits of moons and planets are not circular, but elliptical as Kepler had shown, he had to deal with the "action-at-a-distance" issue, and he had to correctly deal with mass as a generator of gravitational force. For all but the last two of these, Newton came up with definitive descriptions that were not substantially improved upon for more than 300 years. The last two he acknowledged as puzzles that would be left to later generations to fully resolve. We have not fully resolved them yet.
The first thing to note is that the force of gravity must be independent of the type of material since all objects fall with the same acceleration, g. Therefore, the gravitational force must depend on mass alone. The dependence appears to be linear since Fgrav. = mg for an object of mass m. Consider two point masses, m1 and m2, as shown below.
The force acting on m1 should be F12 = m1k1, where k1 depends, at the very least, on the distance between the point masses. We have already established that k1 must be proportional to 1/r122, the distance between the point masses and that the force should be directed along a line connecting the two and pointing toward m2 (the latter comes from the fact that we assumed that the force of attraction for a circular orbit was a central one, i.e. the force connects the centers-of-mass). By the same reasoning, the force acting on m2 should be F21 = m2k2. But, by Newton's Third Law, we must have F21 = F12 and oppositely directed along the line between the point masses and pointing toward m1. The simplest consistent mathematical form is to have
where G is the universal constant of gravitation and must have units of Nt*m2/kg2. Therefore, Newton asserted that the gravitational force between two point masses is proportional to the product of the masses and inversely proportional to the square of the distance between the masses.