Again, just as with the discussion of Galileo's ideas, a lot is being said! The words can be replaced by mathematical equations that condense the length of the statement of these laws, but still, the deep ideas are in there. One "deep" piece of information is that the laws as stated above are not very specific about what we mean by the term "force". Forces are operationally defined. You know a force is acting if something which has a mass is changing its motion. If a force is acting, it is due to an external object acting on the thing whose motion is changing. This says nothing about how the force is exerted!
Many forces are contact forces, i.e. they act only while two objects are physically touching. Other forces are action-at-a-distance forces for which no physical contact is necessary. Examples are gravitional, electrical, and magnetic forces. Newton's Laws of Motion apply to both kinds of forces.
The simplified expression of Newton's Second Law in math-speak is
where Fnet, ext is the net (i.e. the vector sum of all forces), external force acting on an object. The bold face type indicates that force has the characteristics of a vector, namely it must be specified by direction and magnitude. Force is not exactly a vector since you must also specify what the force acts on before it is truly defined. The equation Fnet, ext = ma means we can relate actions to changes in motion, hence the equation a = F/m is referred to as the equation of motion.
The various force types are reviewed briefly here as they are in the Online Textbook.
We should examine each of these more closely to be sure the words used in their description actually form useful ideas when you apply them.
A pictorial example of normal forces for two cases are below. Note that there have to be other forces acting on the objects in order to have the normal forces be non-zero in magnitude, but the directions must always be opposite each other and equal magnitude in accordance with Newton's Third Law, since, by definition, normal forces come from the interaction of objects with each other.
For high school physics courses, the importance of Newton's
Third Law of Motion often gets shrouded in mystery. In fact,
it seems less ``fundamental'' than the first two Laws
as those two ``define'' two important quantities, mass and
force. The Third Law, however, is essential to making the
Second Law consistent in an inertial frame however. In some
sense, the Third Law is necessary to complete the definition
of force because it specifies *how* objects must interact
in order to exert forces on each other. Since all forces
are ultimately the result of an
interaction between objects, you cannot specify a
force until you know what it acts on, and you cannot
specify what it acts on until you know the consistency
rules that govern that interaction. The example below
is a good case in point.
Suppose you have two blocks, labeled A and B. They have masses mA and mB, respectively. These blocks slide without friction.
If the blocks are welded together, then they can be considered as just one object of mass mA + mB. An external force, F applied to this object in the horizontal direction as shown in the figure above must push the object with an acceleration of aAB = F/( mA + mB).
Now suppose the weld is broken so that the blocks are truly separate. When force F is applied to block A as before, the blocks will be kept in contact since A must push on B as long as F is acting as shown in the figure above. As far as the unseeen external object providing force F is concerned, nothing is changed. This object cannot distinguish between the blocks welded or separate but maintaining contact. Therefore, we expect the acceleration of the pair of blocks to remain at aAB = F/( mA + mB). Thus, the forces acting in the horizontal direction on each block must yield this acceleration. The force diagrams for the two are shown below (horizontal direction only).
Note that the force diagram must show a force FBA (read this as the force on B due to A), otherwise we cannot explain block B's acceleration in Newton's scheme that all accelerations must be due to external forces acting on the object. By the same token, we must have a force FAB acting, in the direction shown, on block A, otherwise, the acceleration of block A would have to be higher than aAB (since only block A is being directly affected by force F now). So, we have established that the forces FAB and FBA must be in opposite directions as per Newton's Third Law or we cannot explain why the accelerations of the blocks can both be aAB. What about their relative magnitudes? Here, we resort to quantitative determination of the forces acting in order to explain the accelerations of the blocks. Let the direction to the right be positive. Then, for each block to have acceleration aAB, we need
| Block B: | mB aAB | = FBA |
|---|---|---|
| Block A: | mA aAB | = F - FAB |
Add these two equations together and use our previous result for aAB in terms of F and the masses of the blocks...
| (mA + mB) aAB | = F + FBA - FAB |
| (mA + mB) [F/( mA + mB)] | = F + FBA - FAB |
| F | = F + FBA - FAB ==> |
| FBA | = FAB |
So, the magnitudes of the contact forces are equal and their directions are opposite. The same analysis must hold true for any objects in contact. We always find that the forces they exert on each other must be equal magnitude and opposite directions in order for Newton's Second Law, that accelerations are due only to the net external forces acting, to be consistent.
First, we do the half-Atwood machine.
The free-body diagrams are as shown below
Newton's prescription says that the net force determines the change in motion, hence if we wanted to find the accelerations of the two blocks after they are released, we need to write down for the horizontal motion of mA and the vertical motion of mB.
| mA: | T | = mAa |
| mB: | mBg - T | = mBa |
Note that we listed the accelerations of both blocks as having the same magnitude and sign. We have to be careful in doing this even though it is easy to simply pass this point by. In choosing the directions for our coordinate systems (note that we chose different coordinate systems for each mass), we have determined the relationship between the accelerations of the blocks. mB moves downward. The acceleration must be the same magnitude for both blocks since the string does not change length (hence the amount of rope separating the two blocks stays constant as the blocks accelerate). The signs are the same only because of the coordinate systems we chose. Had the positive direction for mB been upward, then the acceleration of mB and the acceleration of mA would have had opposite signs.
We add our two equations together (after all, they are just algebraic equations now) to get
We could plot this solution for the acceleration, but the equation is simple enough that we can just state some things about it and see that they are true:
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